The lengths of the sides of a triangle are consecutive odd integers. If the perimeter is one less than four times the shortest side, find the length of each side.

x = 1st side

x + 2 = 2nd side

x + 4 = 3rd side

4x - 1 = x + x + 2 + x + 4 {perimeter is one less than shortest side}

4x - 1 = 3x + 6 {combined like terms}

4x = 3x + 7 {added 1 to both sides}

x = 7 {subtracted 3x from both sides}

x + 2 = 9 {substituted 7, in for x, into x + 2}

x + 4 = 11 {substituted 7, in for x, into x + 4}

**7, 9, and 11 **are the lengths of the sides

* - Algebra House*
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