Algebra II

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CTHook CTHook
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Algebra II




Don has 10% ethanol gasoline and 50% ethanol gasoline. If a customer wants 800 liters of 25% ethanol gasoline, how many liters of 10% and 50% ethanol must be mixed?
McGenius McGenius
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Re: Algebra II

Maggie wrote
Don has 10% ethanol gasoline and 50% ethanol gasoline. If a customer wants 800 liters of 25% ethanol gasoline, how many liters of 10% and 50% ethanol must be mixed?
x = liters of 10% ethanol
800 - x = liters of 50% ethanol   800 liters in total

0.1x + 0.5(800 - x) = 0.25(800)
0.1x + 400 - 0.5x = 200   percent liters times number of liters equals total in mixture
-0.4x + 400 = 200   combined like terms
-0.4x = -200   subtracted 400
x = 500   divided by -0.4
800 - x = 300   substituted 500, in for x, into (800 - x)

500 liters of 10% ethanol
300 liters of 50% ethanol

*McGenius*