n = 1st consecutive integer

n + 1 = 2nd consecutive integer

n + 2 = 3rd consecutive integer

n + n + 1 + n + 2 = 57 {sum of the three consecutive integers is 57}

3n + 3 = 57 {combined like terms}

3n = 54 {subtracted 3 from each side}

n = 18 {divided each side by 3}

n + 1 = 19 {substituted 18, in for n, into n + 1}

n + 2 = 20 {substituted 18, in for n, into n + 2}

**18, 19, 20** are the three consecutive integers

*- Algebra House*
**
**