algebra

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algebra

Mark has a total of 41 coins consisting of nickels and quarters the total value of the coins is $4.85 how many of each type of coin does he have
AlgebraHouse AlgebraHouse
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Re: algebra

x = number of nickels
41 - x = number of quarters   {there are a total of 41 coins}

.05x + .25(41 - x) = 4.85   {value of coin times number of coins equals total value}
.05x + 10.25 - .25x = 4.85   {used distributive property}
-.02x + 10.25 = 4.85   {combined like terms}
-.02x = -5.4   {subtracted 10.25 from each side}
x = 27   {divided each side by -.02}
41 - x = 14   {substituted 27, in for x, into 41 - x}

27 nickels and 14 quarters

- Algebra House
lula lula
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Re: algebra

Thanks