interest

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pretty1 pretty1
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interest

A total of $8000 is invested: part at 8% and the remainder at 12%. How much is invested at each rate if the annual interest is $650?
McGenius McGenius
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Re: interest

This post was updated on .
x = part at 8%
8000 - x = part at 12%

.08x + .12(8000 - x) = 650  
.08x + 960 - .12x = 650   distributed
-.04x + 960 = 650   combined
-.04x = -310   subtracted 960
x = 7750   divided

8000 - x = 8000 - 7750 = 250   substituted

$7750 at 8%
$250 at 12%

*McGenius*
pretty1 pretty1
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Re: interest

hi did you solve for the 8% or 9% ?
McGenius McGenius
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Re: interest

pretty1 pretty1
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Re: interest

thank you