math algebra II

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Scooby Scooby
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math algebra II



Proof Proof
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Re: math algebra II

b                    p       3
--  -  d  =  m( --  +  -- )
n                    t        x

b       dn             p      3
--  -  ----  =  m( --  +  -- )   ← got common denominator on left side
n        n              t       x

 b - dn                    p       3
--------  -  d  =  m( --  +  -- )   ← combined numerators over common denominator on left side
    n                       t        x


 b - dn                p       3
--------  -  d  =   --  +  --    ← divided each side by m
   nm                  t        x

bt - dnt       3
--------- =  ---   ← multiplied each side by t/p
 mnp           x

  nmp           x
---------  =  ----   ← took the reciprocal of each side
bt - dnt         3

 3mnp
---------   =  x   ← multiplied each side by 3
bt - dnt

- Proof