Algebra

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Algebra

Find the equation of a line that is perpendicular to 3y+x=2 that passes through (-2,-5)
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Re: Algebra

Find the slope of the given line.

3y + x = 2
3y = -x + 2   ← subtracted x from each side
y = (-1/3)x + (2/3)   ← divided each side by 3

slope = -1/3


Substitute point and slope into slope-intercept form.

(-2,-5) , m = -1/3

y = mx + b
-5 = (-1/3)(-2) + b   ← substituted
-5 = 2/3 + b   ← multiplied
b = -17/3   ← subtracted 2/3 from each side


slope is -1/3 and y-intercept is -17/3

y = (-1/3)x - (17/3)

- Proof