algebra 2

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krisstylecurtis krisstylecurtis
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algebra 2

can you help me solve extraneous solutions on this equation that says 3 square root of x equals 6 can you solve that for me.
thank you
AlgebraHouse AlgebraHouse
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Re: algebra 2

3 √x = 6
√x = 2   {divided each side by 3}
x = 4   {squared each side}

Check back in:
3 √4 = 6   {substituted 4 back in for x}
3(2) = 6  {evaluated the square root of 4}
6 = 6   {multiplied}
It works.

There are no extraneous solutions here.  An extraneous solution is a solution that you get by solving the equation, but when you check it back into the equation, it does not satisfy the equation (make a true statement).

- Algebra House