(3x - 1)/4 + x/2 = 3/8

8[(3x - 1)/4 + x/2 = 3/8] {multiplied entire equation by the least common denominator, 8}

8[(3x - 1)/4] + 8(x/2) = 8(3/8) {multiplied each term by 8}

2(3x - 1) + 4x = 3 {cancelled and multiplied what's left}

6x - 2 + 4x = 3 {used distributive property}

10x - 2 = 3 {combined like terms}

10x = 5 {added 2 to both sides}

**x = 1/2** {divided both sides by 10}

*- Algebra House*
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