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quadratic
A ball is thrown vertically upward from the ground with an initial velocity of 101 ft/sec , Use h=−16t2+v0t+h0 .Determine what the maximum height will be. (Round your answer to two decimal places.)
McGenius
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Re: quadratic
h = 16t² + v0t + h0t
h = 16t² + 101t + 0 substituted 101 for v0 (initial velocity}
Find the ycoordinate of the vertex, which is the maximum height.
maximum height is 159.391 ft
*McGenius*
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